```python
# Question 3: Fixing the error-prone codes
# Below is the code (left) that is encrypted using a number. Once you decrypt the below code,
# it reveals the original code with many errors. Please fix them and explain them using comments (#).
# To decrypt the above code, first, you need to understand how it is encrypted (above right image).
# 1. Fixing the next code will reveal the key.
# 2. Write the decryption function to decrypt the 'encrypted code' to the original code.
# 3. Correct the errors and provide the comments.
# 4. Should show everything in your program file.
# Original, error-prone code
tybony_inevnoyr = "zi_qvpg-xr11inyhr1xr12inyhr2xr13inyhr3"
def encrypt(text, key):
encrypted_text = ""
for char in text:
if char.isalpha():
shifted = ord(char) + key
if char.islower():
if shifted > ord('z'):
shifted -= 26
elif shifted < ord('a'):
shifted += 26
elif char.isupper():
if shifted > ord('Z'):
shifted -= 26
elif shifted < ord('A'):
shifted += 26
encrypted_text += chr(shifted)
else:
encrypted_text += char
return encrypted_text
# Test the encryption function
encrypted_code = encrypt("cebprff_ahzoref", 5)
print(encrypted_code)
# Decryption function
def decrypt(encrypted_text, key):
decrypted_text = ""
for char in encrypted_text:
if char.isalpha():
shifted = ord(char) - key
if char.islower():
if shifted > ord('z'):
shifted -= 26
elif shifted < ord('a'):
shifted += 26
elif char.isupper():
if shifted > ord('Z'):
shifted -= 26
elif shifted < ord('A'):
shifted += 26
decrypted_text += chr(shifted)
else:
decrypted_text += char
return decrypted_text
# Test the decryption function
decrypted_code = decrypt(encrypted_code, 5)
print(decrypted_code)
# Calculating total
total = 0
for i in range(5):
for j in range(3):
if i + j == 5:
total += i + j
else:
total -= i - j
# Decryption key counter
counter = 0
while counter < 5:
if total < 13:
total += 1
elif total > 13:
total -= 1
else:
counter += 2
```