The number of ways to draw more red balls than black balls is the sum of the ways to draw 3 red and 2 black, 4 red and 1 black, and 5 red balls. So, the probability is \( \frac{C(10,3)*C(15,2) + C(10,4)*C(15,1) + C(10,5)}{C(25,5)} \).
(ii) The total number of
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