A ball is drawn at random from box I and transferred to box II. If the probability of drawing a red ball from box I, after this transfer, is $\frac{1}{3}$, then the correct option(s) with the possible values of $n_{1}$ and $n_{2}$ is(are)
(a) $n_{1}=4$ and $n_{2}=6$
(b) $n_{1}=2$ and $n_{2}=3$
(c) $n_{1}=10$ and $n_{2}=20$
(d) $n_{1}=3$ and $n_{2}=6$
Passage - 3 Box 1 contains three cards bearing numbers $1,2,3 ;$ box 2 contains five cards bearing numbers $1,2,3,4,5 ;$ and box 3 contains seven cards bearing numbers $1,2,3,4,5,6,7$. A card is drawn from each of the boxes. Let $x_{i}$ be number on the card drawn from the $i^{\text {th }}$ box, $i=1,2,3$.