Question
If two events $A$ and $B$ are such that $P\left(A^{c}\right)=0.3, P(B)=0.4$ and $P$ $\left(A \cap B^{c}\right)=0.5$, then $P\left(B /\left(A \cup B^{c}\right)\right]=\ldots \ldots \ldots \ldots \ldots \ldots$[1994-2 Marks]
Step 1
3$, $P(B)=0.4$ and $P\left(A \cap B^{c}\right)=0.5$. We know that $P(A) = 1 - P\left(A^{c}\right)$, so $P(A) = 1 - 0.3 = 0.7$. Show more…
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