Question
$A$ and $B$ are two independent events. $C$ is event in which exactly one of $A$ or $B$ occurs. Prove that$P(C) \geq P(A \cup B) P(\bar{A} \cap \bar{B})$
Step 1
Since $C$ is the event in which exactly one of $A$ or $B$ occurs, we can write it as $C = (A \cap \bar{B}) \cup (\bar{A} \cap B)$. Show more…
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