There are four machines and it is known that exactly two of them are faulty. They are tested, one by one, in a random order till both the faulty machines are identified. Then the probability that only two tests are needed is [1998-2 Marks]
(a) $1 / 3$
(b) $1 / 6$
(c) $1 / 2$
(d) $1 / 4$