00:01
In this question we have been given four points.
00:04
So first is a, which is zero zero two.
00:07
Then we have b given as 302, c given as one to one, and then we have d, which is having the coordinate to one four.
00:20
So first of all, we'll try to find out the vector ab, then i will find out the vector ac, and then the vector a, c, and then the vector a, d, which is the vector a, d, which which we need while solving the question.
00:32
So a, we can write as ob minus oa.
00:35
So ob minus oa means what? it comes out to be equal to just three.
00:42
Three, in the component wise, i will write 3 ,00, then i will write this as oc minus oa.
00:48
So this is coming out to be 1, 2 minus 1, okay? and then od minus oa.
00:57
I am writing the coordinate form only, okay? 212 in the first part what we need to calculate calculate v which is the cross product of ab and the vector ac so this is given by i j k and ab it is having 3 .00 and ac is given by 1 2 minus 1 so solving this what we are going to get this determinant if we solve this comes out to be equals to 3 j0 plus 3 j plus 6 times of k.
01:32
So this is the required cross product.
01:35
Then we move to the second question, which is find the equation of the plane p...