00:01
So, here in the question we are given par 60 w a h.
00:11
So, it is 10 log 60 d b.
00:19
So, we get p t as 17 .78 d, then the constant alpha this is 3 .4 d b per 100 feet.
00:40
So, we have a tension for 250 feet.
00:43
So, it is going to be alpha multiplied by 250 divided by 100, which is 3 .4 multiplied by 2 .6.
00:59
This is 260 not 250.
01:01
So, we get the value of l c as 8 .84 d.
01:09
Now, par reach to antenna par reached to antenna it is p t minus l c, which is 17 .78 minus 8 .84, which comes out to be 8 .94 d b, then we have e i r p e i r p, this is p t minus l c plus g a.
01:57
So, we have 17 .78 minus 8 .84 plus 12 that is going to be 20 .94 d b...