00:01
So for part a, we have to find the combined pressure from the atmosphere and from the mass placed.
00:07
So the pressure exerted by the mass is just the weight of the mass divided by the area of the piston.
00:13
So weight of the mass is the mgm, 250 kilograms multiplied by 9 .8 meters per second square, divided by the area of fire square where r should be in meters.
00:23
So that gives the pressure of 3978 -88 pascunas.
00:26
We add that to the atmospheric pressure to get the final pressure here.
00:30
The atmospheric pressure is one bar.
00:32
That's one zero one three to five pascals.
00:34
We add the pressure from the mass, and we get the final pressure of one four one, one three passcals.
00:41
Then part b, we have an isothermal system with a constant temperature, which tells us we can use boils long.
00:47
P1, v1 equals p2, v2.
00:49
So on the left side, for p1, we use the pressure, just the atmospheric pressure before the mass was placed.
00:56
And then we have the volume that's pyre square times h1 and h1 is the original height 1 .2 meters on the right side get the final pressure 141 -113 pascal multiplied by pyres square by h2 multiplied by h2 where h2 is the height they're looking for okay so we rearrange the equation solved for h2 that's the atmospheric pressure divided by the new pressure multiplied by 1 .2 meters and we get 0 .86 meters so the overall length gets smaller decreases to 0 .26 meters so part c here we are dealing with an isobaric system, so constant pressure, which allows us to use charles law.
01:39
V1, v1 divide by t1 equals v2 divide by t2...