Q3 a nozzle is a device for increasing the velocity of a...

'Q3; A nozzle is a device for increasing the velocity of a steadily flowing stream of fluid. At the inlet to a certain nozzle the enthalpy of the fluid is 3025 kJ/kg and the velocity is 60 m/s. At the exit from the nozzle the enthalpy is 2790 kJkg: The nozzle is horizontal and there is negligible heat loss from it, (a) Find the velocity at the nozzle exit: (6) If the inlet area is 0. m and the specific volume at the inlet is 0.19 m"/kg; find the rate of flow of fluid. (c) If the specific volume at the nozzle exit is 0.5 m"/kg; find the exit area of the nozzle.'

Transcript

00:01 In this question we have a specific enthalpy at the inlet nozzle we can write it as h1 which is equal to 3025 kilojoules for kg.

00:10 Then the velocity or at the inlet v1 which is equal to 60 meter per second and we can write this h2 as a specific enthalpy at the existing of the nozzle that is 2790 kilojoule per kg.

00:26 Here there is no heat loss so we can say that q equals to 0 and no work transfer that is w equals to 0 now we want to find out three values so let's start with the first in the first we want to find out the value of a v that is the velocity of the fluid so for that we can write that energy inside which should be equals to energy outside of the nozzle therefore we can write it as m multiplied by h1 plus v1 squared divided by 2 which is equals to q plus m multiplied by h2 plus v2 squared divided by 2.

01:11 Now on further simplification here the mass flow rate remains the same so we can neglect the value of m therefore it becomes h1 plus v1 square divided by 2 which is equal to q plus h2 plus h2 plus v2 squared divided by 2.

01:31 Now let's substitute all the values so it becomes a 3025 plus 60 square divided by 2 which is equals to 0 plus 2790 plus v2 square divided by 2.

01:50 So on simplification we get this value of v2 which is equals to 63 .8 meter per second so this is the answer of a first part that is the velocity of a fluid at the existing at exist exit okay now let's move to the second part in the second part here we can say that a1 be the inlet area and a to be the outlet area here we have a1 which is equal to 0 .1 meter square.

02:27 Then v1 which is equal to 0 .19 meter cube per kg...

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