Q4. Let E be an Archimedean Riesz space, A \(\subseteq\) \(\mathbb{R}\) bounded above. Then show that supremum of the set \(Ax = \{\alpha x : \alpha \in A\}\) exists and \(\sup(Ax) = (\sup A)x\)
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Step 1: Since E is an Archimedean Riesz space, it satisfies the Archimedean property, which states that for any element x in E, there exists a natural number n such that n > x. Show more…
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