Question

Q5-Q4-b A car has the following specification: a- Engine Its power performance function is $P_e = 562.1 \omega_e + 0.89507 \omega_e^2 - 1.4253 \times 10^{-3} \omega_e^3$ Where: $\omega_e$ is the engine angular velocity rad/s. Engine speed in rpm varies from 0 to 7000 rpm. $\omega_e = 2\pi N_e / 60$ rad/s $P_e$ is engine power in W. In all your calculation and plotting engine power should be in kW. $P_{e_{max}} = 255$ kW at 6100 rpm. b- Reduction in the differential 5.5:1 c- Rolling Resistance Coefficient = 0. 01x(1.1 + V/43) d- Drag Coefficient = 0.11 e-Tire size = P245/80 R17 f- Gradient = 1:15 g- Acceleration = 0.33 g (for rotation parts= 0.15 mass of the car) h- Frontal area of the car is 5.2 m² k- Mass of the car = 1385 kg. I-Fuel Consumption relation: $Q_s = \frac{g_e (P_r + P_a + P_o)}{10 \eta V_a \rho_f}$ $Q_s$ is fuel consumption l/100 km where $g_e$ is the optimal specific fuel consumption, g/kWh; $P_r$ is the power required to overcome the rolling resistance of the road, kW; $P_a$ is the power required to overcome the resistance of the air, kW: $P_o$ is the power required to overcome the resistance of the inertial acceleration, kW; $\eta$ is the efficiency of the transmission; $\rho_f$ is the fuel density, kg L$^{-1}$; $V_a$ is the average speed of the vehicle, km h$^{-1}$. $g_e = 125$ g/kWh $\rho_f$ is the fuel density, kg L$^{-1}$ = 0.741 $\eta = 0.93$ 1- Draw the performance Curves. The x axis should be vehicle velocity in km/h. 2- Calculate the maximum vehicle velocity km/h. Check the suitability of this engine to the given car. 3- Calculate the fuel consumption when the car is moving on a level road at a constant velocity of 90 km/h. Then compare with best fuel economy you have founded for a similar car. 4- Calculate the fuel consumption when the car is climbing a gradient (1:15) with the given acceleration.

          Q5-Q4-b A car has the following specification:
a- Engine
Its power performance function is
$P_e = 562.1 \omega_e + 0.89507 \omega_e^2 - 1.4253 \times 10^{-3} \omega_e^3$
Where:
$\omega_e$ is the engine angular velocity rad/s. Engine speed in rpm varies from 0 to 7000 rpm.
$\omega_e = 2\pi N_e / 60$ rad/s
$P_e$ is engine power in W. In all your calculation and plotting engine power should be in kW.
$P_{e_{max}} = 255$ kW at 6100 rpm.
b- Reduction in the differential 5.5:1
c- Rolling Resistance Coefficient = 0. 01x(1.1 + V/43)
d- Drag Coefficient = 0.11
e-Tire size = P245/80 R17
f- Gradient = 1:15
g- Acceleration = 0.33 g (for rotation parts= 0.15 mass of the car)
h- Frontal area of the car is 5.2 m²
k- Mass of the car = 1385 kg.
I-Fuel Consumption relation:
$Q_s = \frac{g_e (P_r + P_a + P_o)}{10 \eta V_a \rho_f}$ 
$Q_s$ is fuel consumption l/100 km
where $g_e$ is the optimal specific fuel consumption, g/kWh; $P_r$ is the power required to overcome the
rolling resistance of the road, kW; $P_a$ is the power required to overcome the resistance of the air, kW:
$P_o$ is the power required to overcome the resistance of the inertial acceleration, kW; $\eta$ is the efficiency
of the transmission; $\rho_f$ is the fuel density, kg L$^{-1}$; $V_a$ is the average speed of the vehicle, km h$^{-1}$.
$g_e = 125$ g/kWh
$\rho_f$ is the fuel density, kg L$^{-1}$ = 0.741
$\eta = 0.93$
1- Draw the performance Curves. The x axis should be vehicle velocity in km/h.
2- Calculate the maximum vehicle velocity km/h. Check the suitability of this engine to the given car.
3- Calculate the fuel consumption when the car is moving on a level road at a constant velocity of 90
km/h. Then compare with best fuel economy you have founded for a similar car.
4- Calculate the fuel consumption when the car is climbing a gradient (1:15) with the given
acceleration.

Q5-Q4-b A car has the following specification:
a- Engine
Its power performance function is
Pe = 562.1 + 0.89507 ^2 - 1.4253 × 10^-3^3
Where:
is the engine angular velocity rad/s. Engine speed in rpm varies from 0 to 7000 rpm.
= 2π Ne / 60 rad/s
Pe is engine power in W. In all your calculation and plotting engine power should be in kW.
Pemax = 255 kW at 6100 rpm.
b- Reduction in the differential 5.5:1
c- Rolling Resistance Coefficient = 0. 01x(1.1 + V/43)
d- Drag Coefficient = 0.11
e-Tire size = P245/80 R17
f- Gradient = 1:15
g- Acceleration = 0.33 g (for rotation parts= 0.15 mass of the car)
h- Frontal area of the car is 5.2 m²
k- Mass of the car = 1385 kg.
I-Fuel Consumption relation:
Qs = (ge (Pr + Pa + Po))/(10 η Va )
Qs is fuel consumption l/100 km
where ge is the optimal specific fuel consumption, g/kWh; Pr is the power required to overcome the
rolling resistance of the road, kW; Pa is the power required to overcome the resistance of the air, kW:
Po is the power required to overcome the resistance of the inertial acceleration, kW; η is the efficiency
of the transmission; is the fuel density, kg L^-1; Va is the average speed of the vehicle, km h^-1.
ge = 125 g/kWh
is the fuel density, kg L^-1 = 0.741
η = 0.93
1- Draw the performance Curves. The x axis should be vehicle velocity in km/h.
2- Calculate the maximum vehicle velocity km/h. Check the suitability of this engine to the given car.
3- Calculate the fuel consumption when the car is moving on a level road at a constant velocity of 90
km/h. Then compare with best fuel economy you have founded for a similar car.
4- Calculate the fuel consumption when the car is climbing a gradient (1:15) with the given
acceleration.

Added by Connor B.

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