Question

Q5. The solution of the differential equation for y(t): d^2y/dt^2 - y = 2 cosh(t), subject to the initial conditions y(0)=0 and dy/dt|_{t=0} = 0, is (A) 1/2 cosh(t)+t sinh(t) (B) -sinh(t)+t cosh(t) (C) t cosh(t) (D) t sinh(t)

          Q5. The solution of the differential equation for y(t): d^2y/dt^2 - y = 2 cosh(t), subject to the initial conditions y(0)=0 and dy/dt|_{t=0} = 0, is
(A) 1/2 cosh(t)+t sinh(t)
(B) -sinh(t)+t cosh(t)
(C) t cosh(t)
(D) t sinh(t)

Added by Joanna P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

04/18/2023

Step 1

Rewrite the given differential equation: $$y'' - y = 2\cosh(t)$$ Show more…

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Q5. The solution of the differential equation for y(t): d^2y/dt^2 - y = 2 cosh(t), subject to the initial conditions y(0) = 0 and dy/dt|_{t=0} = 0, is: (A) 1/2 cosh(t) + t sinh(t) (B) -sinh(t) + t cosh(t) (C) t cosh(t) (D) t sinh(t)