A block of mass 9.4 kg starts from rest at the origin at t = 0 and moves in the positive direction of an x axis. The net force on the block as a function of time is given by the figure 1. What is the momentum of the block at t = 3.0 s? a. 4 kg m/s b. 8 kg m/s c. 3 kg m/s d. 10 kg m/s
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We can do this by integrating the acceleration function with respect to time. ∫a(t) dt = ∫10t^2 dt Integrating, we get: v(t) = (10/3)t^3 + C Show more…
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