Question

Question 1 (1 point) $\lim_{x \to 6} \frac{x-6}{x^2-3x-18}$ is a) $\frac{3}{2}$ b) $\frac{2}{3}$ c) $\frac{1}{9}$ d) $\frac{1}{3}$ e) $\frac{1}{12}$

          Question 1 (1 point)
$\lim_{x \to 6} \frac{x-6}{x^2-3x-18}$ is
a) $\frac{3}{2}$
b) $\frac{2}{3}$
c) $\frac{1}{9}$
d) $\frac{1}{3}$
e) $\frac{1}{12}$

Question 1 (1 point)
limx → 6(x-6)/(x^2-3x-18) is
a) (3)/(2)
b) (2)/(3)
c) (1)/(9)
d) (1)/(3)
e) (1)/(12)

Added by Javier A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sanchit Jain

06/06/2023

Step 1

x^2 - 3x - 18 = (x - 6)(x + 3) Show more…

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Question 1 (1 point) lim_{x->6} \frac{x-6}{x^2-3x-18} is a) 3/2 b) 2/3 c) 1/9 d) 1/3 e) 1/12

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Question 1 (1 point) $\lim_{x \to 6} \frac{x-6}{x^2-3x-18}$ is a) $\frac{3}{2}$ b) $\frac{2}{3}$ c) $\frac{1}{9}$ d) $\frac{1}{3}$ e) $\frac{1}{12}$

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