00:01
In this problem, we are given the probabilities of a basketball player making free throw shots.
00:07
Now, the player has been awarded two free throw shots.
00:10
We need to find the probability that he makes at least one of the two shots.
00:15
So we need to find the probability of him making at least one of the two shots.
00:21
Using the complement rule of probability, this is equal to one minus the probability of the complementary event.
00:27
And the complementary event of the player making at least one shot will be that the player makes none of the shots.
00:35
So that means that the player does not make the first shot and also does not make the second shot.
00:42
Here we consider n1 to be the event that the player does not make the first shot.
00:46
We consider n22 be the event that the player does not make the second free throw shot.
00:52
And intersection represents and so this is what we get.
00:56
Now to find this probability over here, we will use the multiplication rule of probability, and according to that, this is equal to p of n1 times p of n2 given n1.
01:09
So consider p of n1.
01:11
This is the probability of not making the first free throw shot...