00:01
Start with the decision variables as follows x1 to be the x1 to be the amount of labors needed amount of labors needed and x2 will be in terms of amount of wood needed to construct the product amount of wood needed to construct the product so formulation of the problem will be there are three elements that must be included in the objective function here.
00:34
The first is the restriction on the amount of the labour used.
00:38
First one, restriction.
00:41
Second one is the amount of wood that can be used, amount of wood and third one will be in terms of the fact that both variables must have values above zero, that is greater than zero concept.
01:01
Here, so our solution will be in terms of maximum of z is equal to, maximum of z is equal to $400x1 plus $100x2, $100 ,x2, $100 ,000, with subject to the constraints of 8x1 plus 10x2, less than or equal to 80.
01:29
Second constraint will be 2x1 plus 6x2 less than or equal to 36.
01:38
Then third constraint will be x1 less than or equal to 6 and x1 comma x2 that is the non -negativity will be greater than or equal to 0.
01:53
So determining the solution to the problem...