Transpiration is an important mechanism in plants for...

Transpiration is an important mechanism in plants for maintaining water balance. A transpiration experiment was conducted using two plant species and collected data is shown below. Using the information provided, calculate the rate of transpiration of both species at 5 and 15 minutes. Describe how the structure of water allows for the process of transpiration to occur. (4 points) WATER LOSS VERSUS TIME FOR TWO PLANT SPECIES Total Water Loss (mL H2O/100g of tissue) Species A Species B Time (min)

Transcript

00:01 The question says, so here in this question we have been asked to find out or calculate the rate of transpiration using the graph given to us.

00:11 So here we have been provided with the graph and also the outcomes of the experiment conducted by the researcher.

00:18 So based on that, in the time interval of 5 and 15 minutes we have to calculate the transpiration.

00:25 So what is transpiration? transpiration as we all know is nothing but.

00:30 The loss of water molecules from the plant body that is especially from the aerial parts of the plant body that is exposed to the atmosphere that is aially exposed okay and here specifically we have to calculate the rate of transpiration by the graph in the 5 and 15 minute time interval so this is the graph given to us so for species a we'll calculate so first for the rate of transpiration we have to write what is the amount of water lost that is with respect to the time 15 minutes per the 100 gram of tissue okay and also this value has to be minused from that value of the lowest time interval that is the 5 minute that is in the picture or graph you can see it is 1 .2 ml of h2 per hundred hundred grams of tissue and this whole thing should be divided by the time intervals that is from the greatest to the least valued one that is 15 minutes minus five minutes so this is the first part of the problem now if we equate or calculate this we'll get 2 .4 m l of h2 lost per hundred grams of the species a tissue.

02:04 So this is divided by 10 minutes that is 15 minus 5 is 10 minutes.

02:10 So we'll get 0 .24 ml of h2o is lost per 100 grams of tissue per minute.

02:21 Okay so this is the rate of transpiration for species a.

02:26 Likewise we can calculate for this species b what is the rate of inspiration.

02:33 So the same formula is applied for species b.

02:36 Then out of graph we'll get it is 1 .8 m .l minus 0 .4 m l by 15 minus 5 minutes so it will give us 1 .4 divided by 10 that is equal to 0 .14 m l of water molecule or h2 o per hundred grams of the tissues of species b and is lost every minute...

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