Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) A) *Hint-Assume a ? b* ? 9 / ((x + a)(x + b)) dx B) ? ds / (s^2(s - 1)^2) C) ? (x^2 - x + 18) / (x^3 + 3x) dx D) ? (3x^2 + 2x - 3) / (x^3 - x) dx E) ? (x^2 - 8x - 9) / ((x - 1)^2(x^2 + 1)) dx
Added by Jeffrey C.
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It seems like there are some errors in the transcription. I will assume the integral is: $$\int \frac{1244}{x^3 + 3x} dx$$ Now, let's try to simplify the denominator: $$x^3 + 3x = x(x^2 + 3)$$ So, the integral becomes: $$\int \frac{1244}{x(x^2 + 3)} Show more…
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