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QUESTION 1 A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information to find a point estimate for the population proportion of CSCC students who eat lunch on campus. p hat=.26 p=.26 x bar=.26 mu=.26 QUESTION 2 A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information and your calculator to find an interval estimate, at the 95% confidence level, for the population proportion of CSCC students who eat lunch on campus. (.18, .33) (.189, .331) (.189, .330) p=.26 QUESTION 3 We are polling students on the need for more parking on the Columbus Campus here at CSCC. We would like to be 90% certain that we are within 2% of the true population proportion of student who think we need more parking. How big of a sample do we need to take if there are no preliminary point estimates of the population proportion? 1691 1690 1027 1026

          QUESTION 1
A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information to find a point estimate for the population proportion of CSCC students who eat lunch on campus.
p hat=.26
p=.26
x bar=.26
mu=.26

QUESTION 2
A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information and your calculator to find an interval estimate, at the 95% confidence level, for the population proportion of CSCC students who eat lunch on campus.
(.18, .33)
(.189, .331)
(.189, .330)
p=.26

QUESTION 3
We are polling students on the need for more parking on the Columbus Campus here at CSCC. We would like to be 90% certain that we are within 2% of the true population proportion of student who think we need more parking. How big of a sample do we need to take if there are no preliminary point estimates of the population proportion?
1691
1690
1027
1026

Show more…

QUESTION 1
A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information to find a point estimate for the population proportion of CSCC students who eat lunch on campus.
p hat=.26
p=.26
x bar=.26
mu=.26

QUESTION 2
A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information and your calculator to find an interval estimate, at the 95% confidence level, for the population proportion of CSCC students who eat lunch on campus.
(.18, .33)
(.189, .331)
(.189, .330)
p=.26

QUESTION 3
We are polling students on the need for more parking on the Columbus Campus here at CSCC. We would like to be 90% certain that we are within 2% of the true population proportion of student who think we need more parking. How big of a sample do we need to take if there are no preliminary point estimates of the population proportion?
1691
1690
1027
1026

Added by Michael M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert David Nguyen

10/31/2022

Step 1

Given: - Number of students surveyed (n) = 150 - Number of students who eat lunch on campus (x) = 39 Point estimate (p-hat) = x/n = 39/150 = 0.26 ** Show more…

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QUESTION 1 A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information to find a point estimate for the population proportion of CSCC students who eat lunch on campus. p hat=.26 p=.26 x bar=.26 mu=.26 QUESTION 2 A sample of 150 randomly selected CSCC students are surveyed and asked if they eat lunch on campus. 39 indicated that they do eat lunch on campus. Use this information and your calculator to find an interval estimate, at the 95% confidence level, for the population proportion of CSCC students who eat lunch on campus. (.18, .33) (.189, .331) (.189, .330) p=.26 QUESTION 3 We are polling students on the need for more parking on the Columbus Campus here at CSCC. We would like to be 90% certain that we are within 2% of the true population proportion of student who think we need more parking. How big of a sample do we need to take if there are no preliminary point estimates of the population proportion? 1691 1690 1027 1026

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Transcript

00:01 Hi, i'm david and i'm here to help you and see your question.

00:02 Now let me bring up your question here.

00:05 In the question here we have three questions, one, two, and three and there are multiple choice.

00:10 So let me answer it one by one for you.

00:13 In the first question one, we have the symbol size n equal to the 150 and we will have the x equal to the 39 indicated that they do each lunch on campus.

00:27 So from here we need to find the symbol proportion behind.

00:30 It will equal to x over n equal to the 39 over 150 and then we get 309 to the 15 equal to the 1726 therefore the answer for this question here it will be the first option 1 and that's will be the answer for the question 2 now for the question that will be the answer for the question 1 i mean now for the question 2 now we have here the same thing but now we want to compute the 95 % confidence interval for the p, the formula will be the phh plus and minus the critical value z and 4 over 2 times the square root of the pht times 1 minus the phhhh over n.

01:17 Phhht we have found equal to the 026 and the 95 % confidence the critical value equal to 1 .96 times square root the 0 .26, 1 minus 0212 over the n will be the 150.

01:32 And if we compute, we have the 0 .26 plus and minus times 0 .74 divided 1 .50, taking the square root times 1 .96 equal to the 0 .070.

01:49 It will use the minus and equal to the 0 .1898.

01:59 And it will use the plus.

02:00 We have the 0 .26 plus 0 .07 .7...

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