Fc = (1200 kg * (25/3 m/s)^2) / 40 m
Now, we can calculate the frictional force:
Fc = (1200 kg * (625/9 m^2/s^2)) / 40 m
Fc = (750000/9) kg*m/s^2
Fc = 2500 * 5/3 N
So, the frictional force the road applies to the tires is:
$\boxed{F_c = \frac{2500}{3} N}$
b)
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