Question

Question 10 (1 point) Only a horizontal stretch has been applied to the graph of $y = \ln x$ so that the graph of the transformed image graph passes through the point $(8, 1)$. Determine $k$. $k=8e$ $k=e$ $k=8/e$ $k=e/8$

          Question 10 (1 point)
Only a horizontal stretch has been applied to the graph of $y = \ln x$ so that
the graph of the transformed image graph passes through the point $(8, 1)$. Determine $k$.
$k=8e$
$k=e$
$k=8/e$
$k=e/8$

Added by Jasmine E.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Nipun Perera

09/05/2021

Step 1

When a horizontal stretch is applied to the function, the equation becomes y = ln(kx), where k is the horizontal stretch factor. Show more…

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Question 10 (1 point) Only a horizontal stretch has been applied to the graph of y=lnx so that the graph of the transformed image graph passes through the point (8,1). Determine k. k=8e k=e k=(8)/(e) k=(e)/(8) Question 10 (1 point) Only a horizontal stretch has been applied to the graph of y = Inx so that the graph of the transformed image graph passes through the point (8, 1). Determine k k=8e k=e k=8/e k=e/8