00:01
So in this problem, we are giving for problem number three, just to start off with, we're given that f of x is equal to x to the third powered.
00:12
So for the first part, part one, let's call it a.
00:17
F of zero is just going to be zero to the third powered, which is zero.
00:22
For part b, f of negative 2 would be negative 2 to the third powered, which is negative 8.
00:28
For part c, we are supposed to find the value of the function at 2.
00:33
So f of 2 is going to equal 2 to the 3rd powered, which is 8.
00:39
And for part d, we're supposed to simplify f of x plus delta x minus f of x divided by delta x, which will equal to x plus delta x to the third power minus x of the third powered, divided by delta x.
01:00
So this is going to equal to the x plus delta x to the third power.
01:03
We have to expand that.
01:05
And let's see.
01:07
That's going to be x to the third power to begin with plus 3x times, so 3x squared times delta x, plus 3x times delta x squared plus delta x to the third power minus x of the third power...