00:01
Hello student to solve the given question we'll be using the omns law relation that is b equals ir from this relation we need to calculate the current first let us write the series combination from the circuit diagram r d and r e resistors are connected according to the circuit given in series combination so due to the series combination for the equivalent resistance for both of the resistors let us say r dash will be equal to the sum of these two resistors that is three plus five value will be equal to eight oms now r dash and r b and rc these three resistors are connected in parallel combination due to which the equivalent resistance for these three, that is suppose, r double dash, will be calculated as the parallel combination.
01:04
So here, 1 by r double dash will be equal to, to calculate r double dash, we can write the relation as 1 by r dash that is 8 plus 1 by rb, that is 1 by 4, plus 1 by rc that is 1 by 8.
01:22
So from, from, from here we can find the value for r double dash that is equal to 2 oms.
01:30
Next, lastly the resistors pending are ra and rf which will be in series with the r double dash.
01:40
So r double dash, ra and rf are further connected in series combination.
01:49
Hence the equivalent resistance will be finally 2 plus 1 plus 8 .23 that is equal to 11 .23 oms...