00:01
In this problem, it is said that f is a continuous function.
00:04
We have been given some information about it.
00:07
And we have also been given an expression for capital f of x, and we need to find the value of the derivative of capital f of x at the point 2.
00:15
So for that purpose, recall the fundamental theorem of calculus.
00:20
According to that, if we have a function capital f of x, which is the integral from g of x to h of x of x of f of f, d, t, d, t, then f prime x will be equal to f of h of x times h prime x minus f of g of x times g prime x so here we have been given that f of x is equal to the integral from x square to 2x f t d t so f prime x will be f of h x so that's 2x times the derivative of of 2x.
01:03
So what is the derivative of 2x? that will be 2 times the derivative of x, which is 1.
01:08
And from this we subtract f of g of x, g of x squared, and we multiply this with the derivative of g of x, that will be 2x.
01:16
So we end up with 2 times f of 2x minus 2x times f of x squared.
01:24
Now we want to determine f prime 2...