00:01
For question number one, we have the genotype for your heterozygous y and heterozygous r.
00:11
If y and r is on a different chromosome.
00:16
So there will be four gametes, which is we have dominant yr, dominant y, recessive r, recessive y dominant r and recessive yr which is four gametes if the genotype is still heterozygous y and r if your y and r is in the same chromosome so if they have in the same chromosome so there will be no crossing over so there will be two gametes that is y and r and small y and r if your dominant y and recessive r if you have y and recessive r if you have y and recessive r is on the same chromosomes so same chromosome so there will be no crossing over and there will be two gametes that is dominant y small r and we have small y big r which is two gametes so we have also two gametes here.
01:47
If dominant y and also r is on the same chromosome, so there will be 50 % of crossing over.
01:59
So definitely the gametes will be dominant y and r, dominant y, recessive r, recessive y, dominant r, and recessive y and r, which is four gametes.
02:12
For question number two the dihybrid cross between two tall plants with yellow seed will be heterozygous t and y so when we do some test cross definitely the tall yellow will have nine tall green is three the dwarf yellow is all also three and the dwarf green is one and for question number three if we were gonna do some test cross because we have the parents that is heterzygos a b c and dominant d times hetterzygous a recessive b dominant c heterzygous d so this is our parents so definitely if we were going to do some test cross in heterosigos a, so there will be one fourth for dominant a, one half for heterozygos, and one fourth for recessive.
03:42
If we were going to do some test cross to heterozygos b and recessive, so there will be heterozygos b, which is one half, and also we have recessive.
03:58
Which is also one half next part we have also heterzygous c and dominant c so there will be dominant c which is one half and also heterzygous c which is also one half and if we do test cross for dominant d and hatterzygous d so we will have dominant which is one half and also heterozygos which is also one half.
04:36
So the phenotype dominant a, dominant b, dominant c, and dominant d, so we have a, b, c, d is equal to three -fourth.
04:50
So we have three -fourth times one -half times one times one, which is three over eight...