00:01
Hi, today we are solving the question in which mu is given as 36 .6 and given standard deviation is 97, sample size n is equals to 126.
00:15
Now we need to find probability of x lying between 12 .4 and 50 .4.
00:31
So it is equals to here we need to find it out.
00:41
So first of all we first need to standardize the values using the formula z is equals to x minus mu divided by sigma.
00:54
Now where x the value we want to find for probability.
00:59
Mu is the mean population, sigma is given and also we need to find the values.
01:11
So from here if we substitute the values we get it as for x is equals to 12 .4, z is equals to 12 .4 minus 36 .6 divided by 97.
01:33
On solving it we get z is equals to minus 25 .02.
01:42
Now for similarly x is equals to 50 .4 we get z is equals to 12 .50 .4 minus 36 .6 divided by 97.
02:00
On solving it we get it equals to 14 .23.
02:05
Now the probability is essentially 1 since the standard normal distribution is continuous and covers all possible values of z.
02:14
So we can conclude that therefore probability of x lying between 12 .4 and 50 .4 is 1.
02:25
Now secondly we need to find the probability of x lies between 12 .4 and 50 .4.
02:46
Here sample size is 126 and mean is also between this...