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Suppose that you are attempting to determine the necessary sample size required to compute an interval estimate with a margin of error of 14, or no larger than 14.
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Further, suppose that the population standard deviation is known to be 72 and the desired confidence is 95%.
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So that means our critical value would be 1 .96, and we don't, we're looking for that sample size.
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We're going to leave our answer rounded to two decimal places, which is very unconventional, because for these we always round up to the nearest integer, but we're told that d2l doesn't have a roundup feature.
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So we're going to rewrite this, isolating n, and in fact i'm going to go all the way to n.
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So to do that i'm going to take 1 .96 times 72, divided by 14, and then i'm going to square all of that.
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So n is going to be equal to 101 .61...