00:01
The first function is f of t is equals to t root over of t q plus one.
00:09
This is the water flowing rate in t hours.
00:12
So we have to find how much water is flowing in two hours.
00:17
So for this we have to solve indication over 0 to 2 f of t d t using simpson's 1 3rd route.
00:25
Now it's also given that h is equals to 0 .5.
00:28
So we have to find this value up to 3 decibels.
00:32
Places now what is sims as one third rule indication over a to b f of f of x d x is equals to h upon 3 y 0 plus y n plus 4 into y 1 plus y 1 plus y 3 plus y n minus 1 plus 2 into y 2 plus y 2 plus y n minus 2 okay so now what is the relation between n and h so n is is equal to b minus a upon h so here a is equal to 0 and b is equal to 2 so we'll write 2 2 minus 0 upon h that is 0 .5 so n is equals to 4 so it means this interval 0 to 2 has been divided into 4 parts 1, 1, 2, 3, 4.
01:39
Okay, and the length of each subpart is 0 .5.
01:43
So, if this is 0 .5, this is 1 and 1 .5.
01:48
Now, we'll solve the equation that is 0 to 2, f of t, d t, using simpson's 130...