QUESTION 14 - 1 POINT Find the derivative of \( g(x)=2 \sec ^{-1}(x) \) at the point \( x=\frac{9}{5} \). (Enter an exact answer.) Provide your answer below: \[ g^{\prime}\left(\frac{9}{5}\right)= \] \( \square \) FEEDBACK Content attribution
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The derivative of the inverse secant function, \( \sec^{-1}(x) \), can be found using the formula: \[ \frac{d}{dx} \sec^{-1}(x) = \frac{1}{|x|\sqrt{x^2 - 1}} \] for \( |x| > 1 \). Show more…
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