Question

QUESTION 16 The position of an object is given by $\vec{r} = (4.0t^2 + 10.0t + 10.0)\hat{i} + (3.0t^2 + 6.0t + 8.0)\hat{j} + (2.0t^2 + 4.0t + 6.0)\hat{k}$. Where the position is in meters and time is in seconds. Determine the magnitude of the acceleration at time t = 5.0 s 13 m/s² 18 m/s² 11 m/s² 8.4 m/s²

          QUESTION 16
The position of an object is given by
$\vec{r} = (4.0t^2 + 10.0t + 10.0)\hat{i} + (3.0t^2 + 6.0t + 8.0)\hat{j} + (2.0t^2 + 4.0t + 6.0)\hat{k}$.
Where the position is in meters and time is in seconds. Determine the magnitude of the acceleration
at time t = 5.0 s
13 m/s²
18 m/s²
11 m/s²
8.4 m/s²

QUESTION 16
The position of an object is given by
r⃗ = (4.0t^2 + 10.0t + 10.0)î + (3.0t^2 + 6.0t + 8.0)ĵ + (2.0t^2 + 4.0t + 6.0)k̂.
Where the position is in meters and time is in seconds. Determine the magnitude of the acceleration
at time t = 5.0 s
13 m/s²
18 m/s²
11 m/s²
8.4 m/s²

Added by Christopher Z.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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QUESTION 16 The position of an object is given by vec(r)=(4.0t^(2)+10.0t+10.0)hat(i)+(3.0t^(2)+6.0t+8.0)hat(j)+(2.0t^(2)+4.0t+6.0)hat(k). Where the position is in rineters and time is in seconds. Determine the magnitude of the acceleration at time t=5.0s 13(m)/(s^(2)) 18(m)/(s^(2)) 11(m)/(s^(2)) 8.4(m)/(s^(2)) QUESTION 16 The position of an object is given by =(4.0t2+10.0t+10.0+3.0t2+6.0t+8.0+(2.0+4.0t+6.0 Where the position is in meters and time is in seconds. Determine the magnitude of the acceleration at timet=5.0s O13 m/s2 O18 m/s2 O11m/s2 O8.4m/s2