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QUESTION 16 White the expression for K for the reaction below. A^(3+)(aq)+4OH^(-)(aq)=Al(OH)4^(-)(aq) R=([A]^(3+)][OH^(+)] K=([A(OH)_(4)^(-)])/([Al^(34)][OH^(-)]^(4)) K=([Al(OH)_(4)])/([OH^(-)]^(4)) R=([AN^(3)+][OH])/([N(OH)_(4)]) K=([A(OH)_(4)])/([A)^(2))[OH^(*)] QUESTION16 Write the expression for K for the reaction below A3ag+4OHag=AI(OH4aq [HOl[]0 KE A(OH] Ob. [AI(OH KE [HO][] Ocr "(HOV] Ke [OH-] K [HO][V] AOH) Oe K AIOH [HO[]

Name: question 16 white the expression for k for the reaction below a3aq4oh aqaloh4 aq ra3oh kaoh4 al34oh 4 kaloh4oh 4 ran3ohnoh4 kaoh4a2oh question16 write the expression for k for the reacti 29436
Uploaded: 2021-07-07T01:14:43-08:00
Duration: 3 min 22 s
Channel: Eileen Sullivan
Description: question 16 white the expression for k for the reaction below a3aq4oh aqaloh4 aq ra3oh kaoh4 al34oh 4 kaloh4oh 4 ran3ohnoh4 kaoh4a2oh question16 write the expression for k for the reacti 29436

          QUESTION 16
White the expression for K for the reaction below.
A^(3+)(aq)+4OH^(-)(aq)=Al(OH)4^(-)(aq)
R=([A]^(3+)][OH^(+)]
K=([A(OH)_(4)^(-)])/([Al^(34)][OH^(-)]^(4))
K=([Al(OH)_(4)])/([OH^(-)]^(4))
R=([AN^(3)+][OH])/([N(OH)_(4)])
K=([A(OH)_(4)])/([A)^(2))[OH^(*)]
QUESTION16
Write the expression for K for the reaction below A3ag+4OHag=AI(OH4aq [HOl[]0 KE A(OH] Ob. [AI(OH KE [HO][] Ocr "(HOV] Ke [OH-] K [HO][V] AOH) Oe K AIOH [HO[]

question 16 white the expression for k for the reaction below a3aq4oh aqaloh4 aq ra3oh kaoh4 al34oh 4 kaloh4oh 4 ran3ohnoh4 kaoh4a2oh question16 write the expression for k for the reacti 29436

Added by Tina D.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Eileen Sullivan

07/07/2021

Step 1

The reaction is A^(3+)(aq) + 4OH^(-)(aq) = Al(OH)4^(-)(aq). Here, A^(3+)(aq) and 4OH^(-)(aq) are the reactants, and Al(OH)4^(-)(aq) is the product. Show more…

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QUESTION 16 White the expression for K for the reaction below. A^(3+)(aq)+4OH^(-)(aq)=Al(OH)4^(-)(aq) R=([A]^(3+)][OH^(+)] K=([A(OH)_(4)^(-)])/([Al^(34)][OH^(-)]^(4)) K=([Al(OH)_(4)])/([OH^(-)]^(4)) R=([AN^(3)+][OH])/([N(OH)_(4)]) K=([A(OH)_(4)])/([A)^(2))[OH^(*)] QUESTION16 Write the expression for K for the reaction below A3ag+4OHag=AI(OH4aq [HOl[]0 KE A(OH] Ob. [AI(OH KE [HO][] Ocr "(HOV] Ke [OH-] K [HO][V] AOH) Oe K AIOH [HO[]