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Question 17/27 \( 48 \% \) MODULE 12 TEST REVIEW: TRIGONOMETRIC IDENTITIES OLUWATOBILOBA AJ... NEXT PLAY NCP 17 Find the exact value of \( \sin \left(-\frac{5 \pi}{12}\right) \). (A) \( \frac{\sqrt{6}-\sqrt{2}}{4} \) (B) \( \frac{-\sqrt{6}-\sqrt{2}}{4} \) (C) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \) (D) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \)

          Question 17/27
\( 48 \% \)
MODULE 12 TEST REVIEW: TRIGONOMETRIC IDENTITIES
OLUWATOBILOBA AJ...
NEXT
PLAY
NCP

17 Find the exact value of \( \sin \left(-\frac{5 \pi}{12}\right) \).
(A) \( \frac{\sqrt{6}-\sqrt{2}}{4} \)
(B) \( \frac{-\sqrt{6}-\sqrt{2}}{4} \)
(C) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \)
(D) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \)

Question 17/27
48 %
MODULE 12 TEST REVIEW: TRIGONOMETRIC IDENTITIES
OLUWATOBILOBA AJ...
NEXT
PLAY
NCP

17 Find the exact value of sin(-(5 π)/(12)).
(A) (√(6)-√(2))/(4)
(B) (-√(6)-√(2))/(4)
(C) (-√(6)+√(2))/(4)
(D) (-√(6)+√(2))/(4)

Added by Stephen C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Teresa Fuston

Step 1

Step 1: Recognize that \(\sin\left(-\frac{5\pi}{12}\right) = -\sin\left(\frac{5\pi}{12}\right)\) due to the odd property of the sine function. Show more…

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Question 17/27 \( 48 \% \) MODULE 12 TEST REVIEW: TRIGONOMETRIC IDENTITIES OLUWATOBILOBA AJ... NEXT PLAY NCP 17 Find the exact value of \( \sin \left(-\frac{5 \pi}{12}\right) \). (A) \( \frac{\sqrt{6}-\sqrt{2}}{4} \) (B) \( \frac{-\sqrt{6}-\sqrt{2}}{4} \) (C) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \) (D) \( \frac{-\sqrt{6}+\sqrt{2}}{4} \)