A pirate's treasure chest has a rectangular top with a dimension of 1.0 m and 1 m. It lies 16 m below the surface of the ocean. What is the magnitude of the force (in newton) that acts on the rectangular top? (Assume that the atmospheric pressure is 1.0x105 Pa and the density of the sea water is 1000 kg/m3).
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Given: Atmospheric pressure (P atm) = 1.0 x 10^5 Pa Density of seawater (Ļ) = 1000 kg/m^3 Acceleration due to gravity (g) = 9.8 m/s^2 Depth of the chest below the surface (h) = 16m Total pressure (P) = P atm + Ļgh Total pressure (P) = 1.0 x 10^5 + 1000 x 9.8 x Show moreā¦
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