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Question 2 [10 marks] The engine of the helicopter is delivering 450 kW to the rotor shaft AB when the blade is rotating at 1200 rev/min. Determine to the nearest multiples of 5 mm the diameter of the shaft AB if the allowable shear stress is $\tau_{allow}$ = 56 MPa and the angle of twist of the shaft is not to exceed 0.05 rad. The shaft is 0.6 m long and the shear modulus of the shaft material is G = 75 GPa.

Name: question 2 10 marks the engine of the helicopter is delivering 450 kw to the rotor shaft ab when the blade is rotating at 1200 revmin determine to the nearest multiples of 5 mm the diameter 06363
Uploaded: 2025-02-08T05:18:11-08:00
Duration: 2 min 31 s
Channel: Anand Jangid
Description: question 2 10 marks the engine of the helicopter is delivering 450 kw to the rotor shaft ab when the blade is rotating at 1200 revmin determine to the nearest multiples of 5 mm the diameter 06363

          Question 2 [10 marks]
The engine of the helicopter is delivering 450 kW to the rotor shaft AB when the blade is rotating at 1200
rev/min. Determine to the nearest multiples of 5 mm the diameter of the shaft AB if the allowable shear
stress is $\tau_{allow}$ = 56 MPa and the angle of twist of the shaft is not to exceed 0.05 rad. The shaft is 0.6 m
long and the shear modulus of the shaft material is G = 75 GPa.

question 2 10 marks the engine of the helicopter is delivering 450 kw to the rotor shaft ab when the blade is rotating at 1200 revmin determine to the nearest multiples of 5 mm the diameter 06363

Added by Justin M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Anand Jangid

02/08/2025

Step 1

Power: $P = 450 kW = 450 \times 10^3 W$ Rotational speed: $N = 1200 rev/min = \frac{1200}{60} rev/s = 20 rev/s$ Allowable shear stress: $\tau_{allow} = 56 MPa = 56 \times 10^6 Pa$ Angle of twist: $\theta = 0.05 rad$ Shaft length: $L = 0.6 m$ Shear modulus: $G = 75 Show more…

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Question 2 [10 marks] The engine of the helicopter is delivering 450 kW to the rotor shaft AB when the blade is rotating at 1200 rev/min. Determine to the nearest multiples of 5 mm the diameter of the shaft AB if the allowable shear stress is $\tau_{allow}$ = 56 MPa and the angle of twist of the shaft is not to exceed 0.05 rad. The shaft is 0.6 m long and the shear modulus of the shaft material is G = 75 GPa.