Question

Question 2 20 Mg of a solution containing 0.4 kg A/kg solution is cooled slowly to 293 K to form crystals of A.10H2O. What is the yield of crystals if the solubility of A at 293 K is 21.5 kg/100 kg water and during cooling 3 per cent of the original solution is lost by evaporation?

          Question 2
20 Mg of a solution containing 0.4 kg A/kg solution is cooled slowly to 293 K to form
crystals of A.10H2O. What is the yield of crystals if the solubility of A at 293 K is 21.5
kg/100 kg water and during cooling 3 per cent of the original solution is lost by
evaporation?

Question 2
20 Mg of a solution containing 0.4 kg A/kg solution is cooled slowly to 293 K to form
crystals of A.10H2O. What is the yield of crystals if the solubility of A at 293 K is 21.5
kg/100 kg water and during cooling 3 per cent of the original solution is lost by
evaporation?

Added by Becky L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Nicole Krahulik

Step 1

To do this, we need to convert the mass of A in the solution to kilograms. Since the solution contains 0.4 kg A/kg solution, the mass of A in the solution is 20 mg * 0.4 kg A/kg solution = 8 mg A. Show more…

Show all steps

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Question 2: 20 mg of a solution containing 0.4 kg A/kg solution is cooled slowly to 293 K to form crystals of A. 10H2O. What is the yield of crystals if the solubility of A at 293 K is 21.5 kg/100 kg water and during cooling, 3 percent of the original solution is lost by evaporation?