00:01
Hi, in the question the given density function is function of y is equal to e power y for y less than 0 and 0 elsewhere.
00:22
And the a part of question we need to find expected value of e power 3y by 2.
00:29
This is equal to integral minus infinite to infinite e power 3y by 2 multiplied to function of y dy.
00:48
This is equal to integral minus infinite to 0 e power 3y by 2 multiplied to e power y dy is equal to integral minus infinite to 0 e power 5y by 2 dy.
01:06
This is equal to e power 5y by 2 by 2 by 5 from minus infinite to 0 and this is equal to 2 by 5.
01:31
So, the final answer is e of e power 3y by 2 is equal to 2 by 5.
01:46
Now, let us go to b part of the question.
01:50
Moment generating function my t is equal to integral minus infinite to 0 e power ty multiplied to function of y dy.
02:13
This is equal to integral minus infinite to 0 e power ty e power y dy.
02:20
This is equal to integral minus infinite to 0 e power t plus 1 y dy is equal to after integrating we will get e power y multiplied to t plus 1 divided by t plus 1 from minus infinite to 0.
02:45
This is equal to 1 by t plus 1...