Let's rewrite the fraction as:
$$\frac{299 - 8x}{23 + 9x} = \frac{A}{23 + 9x} + \frac{Bx + C}{(23 + 9x)^2}$$
Multiplying both sides by $(23 + 9x)^2$, we get:
$$(299 - 8x)(23 + 9x) = A(23 + 9x) + Bx(23 + 9x) + C$$
Now, we can solve for A, B, and C by comparing
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