Solve for the general solution of the differential equation. y''' - 6y'' + 12y' - 8y = 0 y(t) = C1e^(2t) + C2te^(2t) + C3t^2e^(2t) y(t) = C1e^(-2t) + C2te^(-2t) + C3t^2e^(-2t) y(t) = C1e^(2t) + C2e^(-2t) + C3te^(-2t) y(t) = C1e^(-2t) + C2e^(2t) + C3te^(2t)
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Step 1: Find the auxiliary equation of the given differential equation: $r^2 + 6r + 12 = 8$ Show more…
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