Question

Question 3 [11] A 20-degree full-depth spur pinion is to transmit 1.75 kW at 1200 rpm. If the pinion has 18 teeth with a module of 2, determine a suitable value for the face width based on the Lewis formula if the bending stress should not exceed 75 MPa. [11]

Name: question 3 11 a 20 degree full depth spur pinion is to transmit 175 kw at 1200 rpm if the pinion has 18 teeth with a module of 2 determine a suitable value for the face width based on the le 58891
Uploaded: 2023-03-23T14:20:30-08:00
Duration: 4 min
Channel: Madhur L
Description: question 3 11 a 20 degree full depth spur pinion is to transmit 175 kw at 1200 rpm if the pinion has 18 teeth with a module of 2 determine a suitable value for the face width based on the le 58891

          Question 3
[11]
A 20-degree full-depth spur pinion is to transmit 1.75 kW at 1200 rpm. If the pinion has 18 teeth with a module of 2, determine a suitable value for the face width based on the Lewis formula if the bending stress should not exceed 75 MPa.
[11]

question 3 11 a 20 degree full depth spur pinion is to transmit 175 kw at 1200 rpm if the pinion has 18 teeth with a module of 2 determine a suitable value for the face width based on the le 58891

Added by Katherine B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

03/23/2023

Step 1

First, let's list the given parameters: Pressure angle, $\phi = 20^\circ$ Power transmitted, $P = 1.75 \text{ kW} = 1750 \text{ W}$ Rotational speed, $N = 1200 \text{ rpm}$ Number of teeth on pinion, $Z = 18$ Module, $m = 2 \text{ mm}$ Allowable bending stress, Show more…

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Question 3 [11] A 20-degree full-depth spur pinion is to transmit 1.75 kW at 1200 rpm. If the pinion has 18 teeth with a module of 2, determine a suitable value for the face width based on the Lewis formula if the bending stress should not exceed 75 MPa. [11]