Question 3 6 pts A ball is thrown vertically upward from ground level with a velocity of 80 ft/sec. After \textit{t} seconds, its height above the ground is given by $s(t) = -16t^2 + 80t$ a. When will the ball reach its maximum height? b. What is the maximum height? c. How long is the entire trip? d. What is the ball's velocity when it hits the ground? e. What is the velocity of the ball when it is 96 ft. off the ground? f. What is the speed of the ball when it is 96 ft. off the ground? Show your work for each part with detailed explanation. All answers must be exact. Make sure to include the units of measurements.
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The vertex of a quadratic equation in the form of h(t) = at^2 + bt + c is given by the formula t = -b/2a. In this case, a = 16 and b = 80. Plugging these values into the formula, we get t = -80/(2*16) = -80/32 = -2.5. Since time cannot be negative in this Show more…
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