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Question 3. Score: 0/11 The following histogram plots the proportion of households with at least 1 streaming subscription from years 2015 to 2023 in a sample: Proportion of households with at least 1 subscription service Density 0.000 0.020 50 60 70 80 90 % This is the data for the plot: 52%, 64%, 69%, 74%, 78%, 78%, 83%, 83% a. Describe the shape of the plot in two ways. b. What are the mean and standard deviation of the sample data? What about the median and interquartile range? c. Are there any outliers? Score: N/A/11 Question 4. Score: 0/5 Say that the probability that a person selected at random in SF has used Uber (U), Lyft (L), or Waymo (W) in the past 3 years is as shown in the following Venn diagram: U .37 .17 .10 .01 .05 .02 .02 W L .16 Are Uber, Lyft, and Waymo ridership probabilities mutually independent?

          Question 3. Score: 0/11
The following histogram plots the proportion of households with at least 1 streaming subscription from
years 2015 to 2023 in a sample:
Proportion of households
with at least 1 subscription service
Density
0.000
0.020
50
60
70
80
90
%
This is the data for the plot: 52%, 64%, 69%, 74%, 78%, 78%, 83%, 83%
a. Describe the shape of the plot in two ways.
b. What are the mean and standard deviation of the sample data? What about the median and
interquartile range?
c. Are there any outliers?
Score: N/A/11
Question 4. Score: 0/5
Say that the probability that a person selected at random in SF has used Uber (U), Lyft (L), or Waymo (W) in
the past 3 years is as shown in the following Venn diagram:
U
.37
.17
.10
.01
.05
.02
.02
W
L
.16
Are Uber, Lyft, and Waymo ridership probabilities mutually independent?

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question 3 score 011 the following histogram plots the proportion of households with at least 1 streaming subscription from years 2015 to 2023 in a sample proportion of households with at le 77806

Added by Denise C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert David Nguyen

10/08/2022

Step 1

The histogram is unimodal and roughly symmetric. It could also be described as bell-shaped. b. To calculate the mean and standard deviation, we first convert the percentages to decimal values: 0.52, 0.64, 0.69, 0.74, 0.78, 0.78, 0.83, 0.83. Mean: $\bar{x} = Show more…

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Question 3. Score: 0/11 The following histogram plots the proportion of households with at least 1 streaming subscription from years 2015 to 2023 in a sample: Proportion of households with at least 1 subscription service Density 0.000 0.020 50 60 70 80 90 % This is the data for the plot: 52%, 64%, 69%, 74%, 78%, 78%, 83%, 83% a. Describe the shape of the plot in two ways. b. What are the mean and standard deviation of the sample data? What about the median and interquartile range? c. Are there any outliers? Score: N/A/11 Question 4. Score: 0/5 Say that the probability that a person selected at random in SF has used Uber (U), Lyft (L), or Waymo (W) in the past 3 years is as shown in the following Venn diagram: U .37 .17 .10 .01 .05 .02 .02 W L .16 Are Uber, Lyft, and Waymo ridership probabilities mutually independent?

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Transcript

00:01 Hi, i'm david and i'm here to help you and send your question.

00:03 In the question here, we're given a table of the frequency for the number of the cast -own and the income from the household.

00:10 Now let me bring up the data and put it on the top here.

00:14 And from the data, the first question is 16.

00:17 Asked that you find among the household who own two or more cars, so we'll just focus on this portion here on the data.

00:27 The probability that the household is either the middle or, high income so once you find the probability that the middle i will call it as m high income will be the h m or h given that the number of the car owns so will be i will call this a c to r c 3 plus and then this one just equal to the proportion so we will have to end up on the probability here and then we get it will equal to the 0 .503 plus 0 .077.

01:07 And then the one we are looking for the aim and the arch, it will be this portion only.

01:13 And then we will have on the top will be the 0 .3 plus 0 .0 .03.

01:18 And if you compute, we have the 0 .3 divided by 0 .503 plus 0 .077.

01:27 7, then it gets equal to the zobon 5, 6, 80, 9, 0.

01:35 That will be the question 16.

01:37 And the question 17, once you find the median number of the cars owned by own households, to answer that, we will try to do the cumulative probability and that the number of the count could be small equal to the small c.

01:52 So this one will be starting with the 0 .185.

01:56 From here we add up and then we have the 0 .185.

02:00 We plus the 0 .2 .35 equal to the 0 .42.

02:06 And then we keep ending up.

02:07 Then we have plus 0 .503.

02:11 And we got the 0 .9 -23.

02:14 Now we pay attention to this interval between 0 .41 42 to the 0 .29...

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