00:01
Hi, in this question we are given with the linear set of equations.
00:04
For the first part, we need to write the metric equation that can be written in terms of a x to be equals to b.
00:11
Hence our metric equation would become a for 1 .1, 2, 235 and 357.
00:22
And x can be written as x, y, z where b can be written as 3 ,000.
00:30
7, 12.
00:32
Now moving further for the next part b, where we need to solve these equations using krammers rule.
00:39
For that, first we rewrite the equations as x plus y plus 2z minus 3 is equal to 0.
00:46
2x plus 3y plus 5 z minus 7 is equal to 0.
00:52
3x plus 5y plus 7 z minus 12 is equal to 0.
00:53
3x plus 5y plus 7 z minus 12 is equal to 0.
01:00
Now we will apply kramer's rule to find the values for x, y and z that can be solved as for x by d x that is equals to minus y by d y that would be equal to z by dz that would be equals to minus 1 by d.
01:22
So first we will find d x that can be calculated as d x would be equal to to 1, 2, 3, 3, 5, minus 7, 5, 7 minus 12.
01:39
That can be solved further to find its determinant that would be equals to 3 on solving this further.
01:48
Now moving further for dy, that would be equals to 1, 2, minus 3, 2, 5 minus 7, 3, 3, 7 minus 7, 3, 7 minus 3, 7, 12 and solving this as well we get the result to be equals to minus 2.
02:09
Now solving for d z that would be equals to 1 1 minus 3 2 2 3 minus 7 3 minus 7 3 5 minus 12.
02:20
And solving this further we get this to be equals to minus 1...