Find the indicated root of the given equation to at least four decimal places by using Newton's method. 3x^3-6x^2-x-1=0; between 2 and 3 Hint: Do not assume first value of x exactly between 2 and 3 (=2.5); first determine if the root is closer to 2 or to 3 and then choose first value of x accordingly; it will save you few iterations of Newton's procedure. Examples of anwser: 3.4560, -1.1852
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First, we need to find the derivative of the given function: $f(x) = 3x^3 - 6x^2 - x - 1$. The derivative is $f'(x) = 9x^2 - 12x - 1$. Show more…
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