15.2 A voltage of 200 V is applied to a pure resistor (R), a pure capacitor, C and a lossy inductor coil, all of them connected in parallel. The total current is 2.4 A, while the component currents are 1.5, 2.0 and 1.2 A respectively. Find the total power factor and also the power factor of the coil. Draw the phasor diagram. 15.3 A 200 V. 50Hz supply is connected to a lamp having a rating of 100 V, 200 W, in series with a pure inductance, L, such that the total power consumed is the same, i.e. 200W. Find the value of L. A capacitance, C is now connected across the supply. Find value of C, to bring the supply power factor to unity (1.0). Draw the phasor diagram in the second case.
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- Voltage (V) = 200 V - Total current (I_total) = 2.4 A - Current through resistor (I_R) = 1.5 A - Current through capacitor (I_C) = 2.0 A - Current through inductor coil (I_L) = 1.2 A Show more…
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