Question 4 [30 marks]
(a) Consider a liquid phase reaction between A and B at 25°C:
A + B → T
The rate equation is of the form − r_A = k C_A C_B and the second order rate constant for the reaction is 9.92x10⁻³ m³ kmol⁻¹ s⁻¹.
If the initial concentration of A and B are 0.05 kmol m⁻³ and 1.0 kmol m⁻³, respectively, calculate the time required to convert 70% of the limiting reactant in a batch reactor. [15 marks]
(b) When quinolene, (C₉H₇N) is hydrogenated using pure H₂ at 350°C over a catalyst, the following three reactions can occur (see below) to various extents.
Quinolene (C₉H₇N) → H₂ → Tetrahydroquinolene (C₉H₁₁N)
Tetrahydroquinolene (C₉H₁₁N) → H₂ → Decahydroquinolene (C₉H₁₇N)
Tetrahydroquinolene (C₉H₁₁N) → H₂ → Butylbenzylamine (C₉H₁₃N)
The moles of hydrogen required to convert the reactants in each step can be calculated from increasing hydrogen content in the products.
A charge of 100 moles of quinolene and 500 mol H₂ has been introduced into a batch reactor.
After 10 hours the reactor contents were analysed and the constituents were found to be as follows:
Quinolene (C₉H₇N): 40 mol
Hydrogen (H₂): 290 mol
Decahydroquinolene (C₉H₁₇N): 20 mol
Based on the data provided
(i) Write down the stoichiometric chemical equations for each of the reaction steps. (3 marks)
(ii) State if the amount of H₂ charged into the reactor is sufficient to convert Quinolene to products completely. (3 marks)
(iii) Determine the amounts (in moles) of tetrahydroquinolene (C₉H₁₁N) and butylbenzylamine (C₉H₁₃N) after 10 hours. (9 marks)