00:01
Here's our function, which is the product of two functions that have derivatives that all orders.
00:06
So to get the first derivative, we are going to use the chain rule.
00:10
I'm not going to write the of x just for conciseness.
00:13
So we take the derivative of f and then multiply it by g.
00:17
And then we'll take the derivative of g and multiply it by f.
00:21
And that's our first derivative.
00:23
Then to get the second derivative, we're going to take basically the pro.
00:28
It's going to be four terms.
00:30
Then we might not be able to combine like terms.
00:32
So it's the second derivative of f times g plus we'll differentiate with respect to g.
00:40
And then we'll take this second term here.
00:42
So basically that goes with that.
00:45
And then for this term, we have the derivative of g.
00:51
And then we'll take their derivative with respect to, i'm sorry, with f and then with respect to g.
00:57
And then these two terms in the middle, because it's just multiplication, it doesn't matter what order we write the f and the g.
01:04
So that's equivalent to two times the derivative of f times the derivative of g.
01:09
And therefore we have the same expression that's given in the problem and we've shown that that's true.
01:14
Then we'll take the third derivative.
01:19
We'll use the simplified expression.
01:23
So let me just write it in blue just so we're clear on all the terms.
01:34
I'm basically just copying the terms over.
01:38
Okay.
01:39
So we have the third derivative of f times the derivative with respect to g, i mean times g, and then we'll take the derivative with respect to g.
01:50
That's term number one.
01:52
And then we have two differentiate with respect to f plus two times differentiate with respect to g plus two more terms.
02:09
Differency with respect to g and then with respect to f.
02:16
Like so...