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Question 45 What will happen to a red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water? Select one: a. The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC. b. The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC. c. The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC. d. The cell will remain the same size because the solution outside the cell is isotonic.

          Question 45
What will happen to a red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water?

Select one:
a. The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
b. The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC.
c. The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
d. The cell will remain the same size because the solution outside the cell is isotonic.

Question 45
What will happen to a red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water?

Select one:
a. The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
b. The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC.
c. The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
d. The cell will remain the same size because the solution outside the cell is isotonic.

Added by Victoria H.

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