00:01
Hello everyone, if we calculate number of moles of naoh at equivalence point, we will get 1 .25 mole per liter multiplied by 35 .38 ml multiplied by 1 liter divided by 10 power 3 ml.
00:29
We will get 0 .04225 mole.
00:37
So the total volume of solution is 60 .38 ml.
00:49
So the reaction, it is ha plus naoh.
00:55
This gives naa plus h2o.
01:01
So total moles of naoh we have 0 .04442 .2.
01:06
Now the chemical equation it shows that 1 mole of naa which uses 1 mole of ha therefore total moles of h a neutralized is also 0 .04225.
01:21
So now salt dissociates as naa n a plus plus a minus now the equivalence point it will be a is equal to moles of a divided by the total volume of solution 0 .04225 divided by 60 .38 multiplied by 10 par minus 3.
01:52
So from here, a is equals to 0 .732m.
01:58
So ph at equivalence point will be ph is equal to 7 plus half of pka plus log z and this will be 8.
02:15
8 .37 is equal to 7 plus half of pca plus log 0 .732.
02:26
So from here we'll get pca plus log 0 .732 is equal to 2 .39.
02:40
So from here we'll get pca plus log 0 .732 is equal to 2 .39.
02:41
So from here we'll get pca is equal to 2 .5264...