Question 5 3 pts Determine the vertical asymptotes of $f(x) = \frac{1}{x^3 - 25x}$. State the solutions in ascending order. The vertical asymptotes are the lines $x = \text{_____}$, $x = \text{_____}$, and $x = \text{_____}$.
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The denominator is $x^3 - 25x$. We set it to zero and solve for $x$: $x^3 - 25x = 0$ $x(x^2 - 25) = 0$ $x(x - 5)(x + 5) = 0$ This gives us three solutions: $x = 0$, $x = 5$, and $x = -5$. Show more…
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